Integrand size = 34, antiderivative size = 28 \[ \int \frac {(a B+b B \cos (c+d x)) \sec ^4(c+d x)}{a+b \cos (c+d x)} \, dx=\frac {B \tan (c+d x)}{d}+\frac {B \tan ^3(c+d x)}{3 d} \]
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Time = 0.02 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.059, Rules used = {21, 3852} \[ \int \frac {(a B+b B \cos (c+d x)) \sec ^4(c+d x)}{a+b \cos (c+d x)} \, dx=\frac {B \tan ^3(c+d x)}{3 d}+\frac {B \tan (c+d x)}{d} \]
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Rule 21
Rule 3852
Rubi steps \begin{align*} \text {integral}& = B \int \sec ^4(c+d x) \, dx \\ & = -\frac {B \text {Subst}\left (\int \left (1+x^2\right ) \, dx,x,-\tan (c+d x)\right )}{d} \\ & = \frac {B \tan (c+d x)}{d}+\frac {B \tan ^3(c+d x)}{3 d} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.86 \[ \int \frac {(a B+b B \cos (c+d x)) \sec ^4(c+d x)}{a+b \cos (c+d x)} \, dx=\frac {B \left (\tan (c+d x)+\frac {1}{3} \tan ^3(c+d x)\right )}{d} \]
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Time = 1.77 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.89
method | result | size |
derivativedivides | \(-\frac {B \left (-\frac {2}{3}-\frac {\left (\sec ^{2}\left (d x +c \right )\right )}{3}\right ) \tan \left (d x +c \right )}{d}\) | \(25\) |
default | \(-\frac {B \left (-\frac {2}{3}-\frac {\left (\sec ^{2}\left (d x +c \right )\right )}{3}\right ) \tan \left (d x +c \right )}{d}\) | \(25\) |
risch | \(\frac {4 i B \left (3 \,{\mathrm e}^{2 i \left (d x +c \right )}+1\right )}{3 d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{3}}\) | \(34\) |
parallelrisch | \(-\frac {2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )-\frac {2 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3}+1\right ) B}{d \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )^{3} \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{3}}\) | \(68\) |
norman | \(\frac {-\frac {2 B \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{d}-\frac {2 B \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 d}-\frac {2 B \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 d}-\frac {2 B \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )^{3}}\) | \(99\) |
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Time = 0.26 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.14 \[ \int \frac {(a B+b B \cos (c+d x)) \sec ^4(c+d x)}{a+b \cos (c+d x)} \, dx=\frac {{\left (2 \, B \cos \left (d x + c\right )^{2} + B\right )} \sin \left (d x + c\right )}{3 \, d \cos \left (d x + c\right )^{3}} \]
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Time = 8.07 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.50 \[ \int \frac {(a B+b B \cos (c+d x)) \sec ^4(c+d x)}{a+b \cos (c+d x)} \, dx=\begin {cases} \frac {B \left (\frac {\tan ^{3}{\left (c + d x \right )}}{3} + \tan {\left (c + d x \right )}\right )}{d} & \text {for}\: d \neq 0 \\\frac {x \left (B a + B b \cos {\left (c \right )}\right ) \sec ^{4}{\left (c \right )}}{a + b \cos {\left (c \right )}} & \text {otherwise} \end {cases} \]
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Exception generated. \[ \int \frac {(a B+b B \cos (c+d x)) \sec ^4(c+d x)}{a+b \cos (c+d x)} \, dx=\text {Exception raised: ValueError} \]
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Time = 0.29 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.89 \[ \int \frac {(a B+b B \cos (c+d x)) \sec ^4(c+d x)}{a+b \cos (c+d x)} \, dx=\frac {B \tan \left (d x + c\right )^{3} + 3 \, B \tan \left (d x + c\right )}{3 \, d} \]
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Time = 0.69 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.39 \[ \int \frac {(a B+b B \cos (c+d x)) \sec ^4(c+d x)}{a+b \cos (c+d x)} \, dx=\frac {2\,B\,\sin \left (c+d\,x\right )\,{\cos \left (c+d\,x\right )}^2+B\,\sin \left (c+d\,x\right )}{3\,d\,{\cos \left (c+d\,x\right )}^3} \]
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